2[7-3(2+3x-4)]+1=

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Solution for 2[7-3(2+3x-4)]+1= equation:


Simplifying
2[7 + -3(2 + 3x + -4)] + 1 = 0

Reorder the terms:
2[7 + -3(2 + -4 + 3x)] + 1 = 0

Combine like terms: 2 + -4 = -2
2[7 + -3(-2 + 3x)] + 1 = 0
2[7 + (-2 * -3 + 3x * -3)] + 1 = 0
2[7 + (6 + -9x)] + 1 = 0

Combine like terms: 7 + 6 = 13
2[13 + -9x] + 1 = 0
[13 * 2 + -9x * 2] + 1 = 0
[26 + -18x] + 1 = 0

Reorder the terms:
26 + 1 + -18x = 0

Combine like terms: 26 + 1 = 27
27 + -18x = 0

Solving
27 + -18x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-27' to each side of the equation.
27 + -27 + -18x = 0 + -27

Combine like terms: 27 + -27 = 0
0 + -18x = 0 + -27
-18x = 0 + -27

Combine like terms: 0 + -27 = -27
-18x = -27

Divide each side by '-18'.
x = 1.5

Simplifying
x = 1.5

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